WebFind the A.P. whose sum to n terms is 2n 2 +n A The required A.P. is 2,6,10,14,... B The required A.P. is 3,7,11,15,... C The required A.P. is 4,8,12,16,... D The required A.P. is 5,10,15,20,... Medium Solution Verified by Toppr Correct option is B) Given, S n=2n 2+n Now, a 1=S 1=2(1) 2+1=3 a 2=S 2−S 1=2(2) 2+2−3=7 WebMar 30, 2024 · The sum of first n terms of an AP is given by S n = 2n 2 + 3n . Find the sixteenth term of the AP. Find the sixteenth term of the AP. This is a question of CBSE Sample Paper - Class 10 - 2024/18.
Partial sums: formula for nth term from partial sum
WebAug 26, 2024 · In an AP, if Sn = n (4n + 1), then find the AP. arithmetic progression class-10 1 Answer +1 vote answered Aug 26, 2024 by Sima02 (49.6k points) selected Aug 26, 2024 … WebEnglish Medium Class 10 In an AP, if Sn = n (4n + 1), find the AP. - Mathematics Advertisement Remove all ads Advertisement Remove all ads Sum In an AP, if S n = n (4n … how to snap vinyl flooring together
Question 24In an AP, if Sn=n4 n+1, then find the AP.
WebJan 27, 2024 · In an AP if Sn = n(4n + 1) then Find the AP - YouTube In an AP if Sn = n(4n + 1) then Find the AP In an AP if Sn = n(4n + 1) then Find the AP... WebCorrect option is A) Given, S n=4n 2−n When n=1 , S 1=4(1) 2−1=4−1=3 Now, obviously, the sum of the first term will be the first term itself, as there are no other terms involved. When n=2 , S 2=4(2) 2−1=16=2=14 The sum of the first 2 terms is equal to a 1+a 2 Therefore, a 1+a 2=14 We have shown, above, that a 1=3 Substituting it in a 1+a 2=14, WebGiven that sn = 4n^2 + 2n. ----- (1) Substitute n = 1 in (1), we get sn = 4(1)^2 + 2(1) = 4 + 2 = 6. So, Sum of the first term of AP is 6 i.e a = 6. Now, Substitute n = 2 in (1), we get sn = 4(2)^2 + 2(2) = 4 * 4 + 2 * 2 = 16 + 4 = 20. So, Sum of the first 2 terms = 20. Now, First-term + second term = 20 6 + a2 = 20 a2 = 20 - 6 a2 = 4. Hence in AP, how to snap your own back